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Pauli's Exclusion Principle

Quantum numbe...

Question

Quantum numbers of an atom can be defined on the basis of :

A

Hund's rule

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B

Pauli's exclusion principle

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C

Autbau's principle

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D

Heisenberg's uncertainity principle

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Solution

The correct option is B Pauli's exclusion principle
Quantum numbers of an atom can be defined on the basis of Pauli's exclusion principle. The Pauli Exclusion Principle states that, in an atom or molecule, no two electrons can have the same four electronic quantum numbers. As an orbital can contain a maximum of only two electrons, the two electrons must have opposing spins. This means if one is assigned an up-spin ( +1/2), the other must be down-spin (-1/2).

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Similar questions

Q. If nitrogen atom had an electronic configuration of

1 s^{7}

, it would have energy lower than it’s normal ground state configuration of

1 s^{2} 2 s^{2} 2 p^{3} . Y e t, 1 s^{7}

is not observed as it violates:

Q. According to Pauli's exclusion principle, no two electrons in an atom can have same values for all the four quantum numbers.

Q. Instead of Principal quantum number

(n)

, Azimuthal quantum number

(l)

and Magnetic quantum number

(m)

, a set of new quantum number

S

t

u

was introduced with similar logic but different values as defined below:

S = 1, 2, 3 \dots \dots

(all positive integral values)

t = (S^{2} - 1^{2}), (S^{2} - 2^{2}), (S^{2} - 3^{2}) \dots \dots

No negative values

u = - \frac{(t + 1)}{2}

\frac{(t + 1)}{2}

in integral steps.
Each orbital can have maximum four electrons.

(S + t)

rule is defined similar to

(n + l)

rule.
Now answer the following questions:

Number of electrons belongs to

S = 2

t = 3

for an element with atomic number

Z = 24

If carbon atom has electronic configuration 1 $s^{6}$ , it would have energy lower than that of the normal ground state configuration 1 $s^{2}$ 2 $s^{2}$ 2 $p^{2}$ . Yet 1 $s^{6}$ is not observed because it violates

Q. If the nitrogen atom had an electronic configuration of

1 s^{7}

it would have lower energy than that of the normal ground state configuration

1 s^{2}, 2 s^{2}, 2 p^{3}

because the electrons would be closer to the nucleus.

1 s^{7}

is not observed because it violates:

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