Quarter non-conducting disc of radius 4R having uniform surface charge density σ is placed in xz-plane, then which of the following is correct?
A
Electric potential at (0,3R,0)isσR4ϵ0
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B
Electric potential at (0,0,0) is σR2ϵ0
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C
Electric field at (0,3R,0) is symmetric with x and z axis
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D
Electric field intensity at (-4R, 0, -4R) is equally inclined with x and z axis
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Solution
The correct options are A Electric potential at (0,3R,0)isσR4ϵ0 B Electric potential at (0,0,0) is σR2ϵ0 C Electric field at (0,3R,0) is symmetric with x and z axis D Electric field intensity at (-4R, 0, -4R) is equally inclined with x and z axis (A)V=∫4R0Kπ2rdrσ√r2+(3R)2=σR4ϵ0 (B)V=∫4R0Kπ2rdrσr=σR2ϵ0 (C) Given point is symmetric w.r.t x-axis and z-axis. (D) Given point is symmetric w.r.t x-axis and z-axis.