ques 17
17 Water falls from height of 50 m .calculate the rise in temperature of water when its strikes the bottom (g=10 ms^-2,sp, heat capacity of water =4200j/kg^oC

Open in App

Solution

Dear Student ,
Here in this case ,

$m g h = m s t \Rightarrow t = \frac{g h}{s} \Rightarrow t = \frac{50 \times 10}{4200} = 0 \cdot 12 ° C$

Regards

Suggest Corrections

Similar questions

Q. Water falls from a height of 50 cm. Calculate the rise in temperature of water when it strikes the bottom. (

g = 10 m s^{- 2}

, sp. heat capacity of water

= 4200 J / k g^{o} C

)

Water falls from a height of 50 m. Calculate the rise in temperature of water when it strikes the bottom. Take g = 10 m s^-2 and specific heat capacity of water = 4200 J kg^-1 °C^-1).

Water falls from a height of 100 m. Calculate the rise in temperature of water when it strikes the bottom. Given, S $_{w}$ = 4200 Jkg $^{- 1}$ $^{0}$ C $^{- 1}$ and g = 10 m/s $^{2}$ .

Q. Water falls from a height of 100 m. Find the rise in temperature of the water when it reaches the bottom, assuming all its energy is converted to heat at the bottom of the waterfall.

(g = 10 m s^{- 2}, s_{w} = 4200 J k g^{- 1} K^{- 1})

Q. Water falls from a height of 500 m. What is approximately the rise temperature of water at bottom if whole energy is used to heat the water?

Join BYJU'S Learning Program

ques 17 17 Water falls from height of 50 m .calculate the rise in temperature of water when its strikes the bottom (g=10 ms-2,sp, heat capacity of water =4200j/kgoC

Dear Student , Here in this case , mgh=mst⇒t=ghs⇒t=50×104200=0·12 °C Regards

ques 17
17 Water falls from height of 50 m .calculate the rise in temperature of water when its strikes the bottom (g=10 ms^-2,sp, heat capacity of water =4200j/kg^oC

Dear Student ,
Here in this case ,

$m g h = m s t \Rightarrow t = \frac{g h}{s} \Rightarrow t = \frac{50 \times 10}{4200} = 0 \cdot 12 ° C$

Regards