Question

Question 07.
Apoorv throws two dice once and computers the product of the numbers appearing on the dice. Peehu throws one die and squares the number that appears on it. Who has the better chance of getting the number 36 ? why ?

Answer 1

Aprrorv throws two dice once.
Number of outcomes for getting product $36=1(6\times 6)$
$\therefore$ Probability for Apoorv $=\frac{1}{36}$
Also, Peehu throws one die,
So, total number of outcomes = 6
Number of outcomes for getting square $36=1(6^2=36)$
$\therefore$ Probability for Peehu $=\frac{1}{6}=\frac{6}{36}$
Hence, Peehu has better chance of getting the number 36.