Question 09.
A student says that, if you throw a die, it will show up 1 or not 1. Therefore, the probability of getting 1 and the probability of getting not 1 each is equal to $\frac{1}{2}$ . Is this correct ? Give reasons.

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Solution

No, this is not correct.
Suppose we throw a die, then total number of outcomes = 6
Possible outcomes = 1 or 2 or 3 or 4 or 5 or 6
$∴$ Probability of getting $1 = \frac{1}{6}$
Now, Probability of getting not 1 = 1 - Probability of getting 1
$= 1 - \frac{1}{6} = \frac{5}{6}$

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Q. Question 25 (ii)
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\frac{1}{2}

Which of the following arguments are correct and which are not correct? Give reasons for your answer.

(i) If two coins are tossed simultaneously there are three possible outcomes−−two heads, two tails or one of each. Therefore, for each of these outcomes, the probability is.

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Q. Question 11.
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Probability of an Event

Standard VIII Mathematics

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Question 09. A student says that, if you throw a die, it will show up 1 or not 1. Therefore, the probability of getting 1 and the probability of getting not 1 each is equal to 12. Is this correct ? Give reasons.

No, this is not correct. Suppose we throw a die, then total number of outcomes = 6 Possible outcomes = 1 or 2 or 3 or 4 or 5 or 6 ∴ Probability of getting 1=16 Now, Probability of getting not 1 = 1 - Probability of getting 1 =1−16=56

Question 09.
A student says that, if you throw a die, it will show up 1 or not 1. Therefore, the probability of getting 1 and the probability of getting not 1 each is equal to $\frac{1}{2}$ . Is this correct ? Give reasons.

No, this is not correct.
Suppose we throw a die, then total number of outcomes = 6
Possible outcomes = 1 or 2 or 3 or 4 or 5 or 6
$∴$ Probability of getting $1 = \frac{1}{6}$
Now, Probability of getting not 1 = 1 - Probability of getting 1
$= 1 - \frac{1}{6} = \frac{5}{6}$