Question 1-35 Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction- CaCO3-s- - 2 HCl-aq- rarr-CaCl2-aq- - CO2-g- - H2O-l- What mass of CaCO3 is required to react completely with 25 mL of 0-75 M HCl-

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Standard XII

Chemistry

Equivalent Mass

Question 1.35...

Question

Question 1.35 Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction, CaCO3(s) + 2 HCl(aq)→CaCl2(aq) + CO2(g) + H2O(l) What mass of CaCO3 is required to react completely with 25 mL of 0.75 M HCl?

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Solution

1 mole of CaCO3 needs 2 moles of HCl, given HCl = 25 x0.75 millimoles = 18.75 millimoles so millimoles of CaCO3 needed = 18.75 /2 or 18.75/2000 mole and so grams will be, given mass = mole x molar mass =(18.75 /2000) x 100 g

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