Given, diameter of the circular track,
D=200 m, radius of the circular track,
r=2002=100 m and time taken by the athlete in one round,
t=40 s
![](https://infinitestudent-migration-images.s3-us-west-2.amazonaws.com/_41dd135ea3b2c647d95f0808648baf124947d8d120160916-14462-1ko42qn.png)
Distance covered by the athlete in one round,
s=2πr
=2×227×100
Speed of the athlete,
v=distancetime
=2×22007×40
=44007×40
Therefore, distance covered in 2 minutes 20 s = Speed(s)
× Time (t)
=44007×40×(2×60+20)
=44007×40×140
=2200 m
Number of round in 40 s = 1 round
Number of round in 140 s
=14040 =3.5
After starting from position X, the athlete will be at position Y after 3.5 rounds as shown in figure.
Hence, displacement of the athlete with respect to initial position = Diameter of the track
= 200m