Question 1 iFind 641-2 -

Name: NCERT - Grade 09 - Mathematics - Number Systems - Q24_1
Uploaded: 2022-07-04T10:36:42+05:30
Description: 64^1/2 = ( 2^6 )^1/2 [∵ 64=2^6] =2^6 ×1/2=2^3=8 [∵ (a^m)^n= a^mn] ...

64^1/2 = ( 2^6 )^1/2 [∵ 64=2^6] =2^6 ×1/2=2^3=8 [∵ (a^m)^n= a^mn] ...

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Standard VII

Mathematics

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Question 1 iF...

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Question 1 (i)
Find $64^{\frac{1}{2}}$ .

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Solution

$64^{\frac{1}{2}}$

$= {(2^{6})}^{\frac{1}{2}} [∵ 64 = 2^{6}]$

$= 2^{6 \times \frac{1}{2}} = 2^{3} = 8 [∵ (a^{m})^{n} = a^{m n}]$

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Standard VII Mathematics

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Question 1 (i) Find 6412 .

6412 =(26)12 [∵ 64=26] =26×12=23=8 [∵ (am)n=amn]

Question 1 (i)
Find $64^{\frac{1}{2}}$ .

$64^{\frac{1}{2}}$

$= {(2^{6})}^{\frac{1}{2}} [∵ 64 = 2^{6}]$

$= 2^{6 \times \frac{1}{2}} = 2^{3} = 8 [∵ (a^{m})^{n} = a^{m n}]$