Question

Question 1 (i)
Find the square roots of each of the following numbers by Division method:

2304

Answer 1

2304

$\begin{array}{cc}& 48\\ 4& \overline{23}\overline{04}\\ & -16\\ 88& 704\\ & -704\\ & 0\end{array}$
Steps
Step(i)2304 is dividend. Pair it in groups of 2 digits i.e $\overline{23}\overline{04}$
Step(ii)Now for divisor,find the perfect square which is not greater than 23 which is $16\left(4^2\right)<23<25\left(5^2\right)$
Step (iii)andNow take 4 as divisor and
$\begin{array}{cc}& 4\\ 4& \overline{23}\overline{04}\\ & -16\\ & 7\end{array}$
Step(iv)Now for new divisior double the old divisior and find a digit such that product of digit and the new divisor appended with that digit is the biggest number not greater than the new dividend and perform the division $(88\times 8=704$)
$\begin{array}{cc}88& 704\\ & -704\\ & 0\end{array}$

Hence, the square root of 2304 is 48.