Question

Question 1(ii)
Carry out the division.
$-36y^3÷9y^2$

Answer 1

$36y^3=2\times 2\times 3\times 3\times y\times y\times y9y^2=3\times 3\times y\times y-36y3÷9y^2=-\frac{2\times 2\times 3\times 3\times y\times y\times y}{3\times 3\times y\times y}=-4y$