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Question

Question 1 (ii)
Find the area of the triangle whose vertices are:
(ii) (-5, -1), (3, -5), (5, 2)

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Solution

Let (x1,y1)=(5,1), (x2,y2)=(3,5) and (x3,y3)=(5,2),
Area of a triangle
=12{x1(y2y3)+x2(y3y1)+x3(y1y2)}
=12[5{(5)(2)}+3(2(1))+5{1(5)}]
= 12{35+9+20}
= 32 square units

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