Question 1 iiiWithout actually performing the long division- state whether 64-455 will have a terminating decimal expansion or a non-terminating repeating decimal expansion-

Name: NCERT - Grade 10 - Mathematics - Real Numbers - Q16_3
Uploaded: 2022-07-04T10:36:42+05:30
Description: 64/455 Factorize the denominator; we get, 455 = 5 × 7 × 13 The nbsp;denominator is not in the form of 2^m× 5^n, as there are other prime factors as well. Henc ...

64/455 Factorize the denominator; we get, 455 = 5 × 7 × 13 The nbsp;denominator is not in the form of 2^m× 5^n, as there are other prime factors as well. Henc ...

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Standard X

Mathematics

Check If a Given Rational No. Is Terminating or Not

Question 1 ii...

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Question 1 (iii)
Without actually performing the long division, state whether $\frac{64}{455}$ will have a terminating decimal expansion or a non-terminating repeating decimal expansion.

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Solution

$\frac{64}{455}$
Factorize the denominator; we get,
$455 = 5 \times 7 \times 13$
The denominator is not in the form of $2^{m} \times 5^{n}$ , as there are other prime factors as well.
Hence, the decimal expansion of the given number is recurring (repeating).

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Without actually performing the long division, state whether the following rational number will have a terminating or a non-terminating repeating decimal expansion.

\frac{64}{455}

Q. Question 1 (iii)
Without actually performing the long division, state whether the following rational numbers will have a terminating decimal expansion or a non-terminating repeating decimal expansion:

\frac{64}{455}

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Question 1 (iii) Without actually performing the long division, state whether 64455 will have a terminating decimal expansion or a non-terminating repeating decimal expansion.

64455 Factorize the denominator; we get, 455=5×7×13 The denominator is not in the form of 2m×5n, as there are other prime factors as well. Hence, the decimal expansion of the given number is recurring (repeating).

Question 1 (iii)
Without actually performing the long division, state whether $\frac{64}{455}$ will have a terminating decimal expansion or a non-terminating repeating decimal expansion.

$\frac{64}{455}$
Factorize the denominator; we get,
$455 = 5 \times 7 \times 13$
The denominator is not in the form of $2^{m} \times 5^{n}$ , as there are other prime factors as well.
Hence, the decimal expansion of the given number is recurring (repeating).