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Question

Question 1 (iv)
Find the sum of the following APs
(iv) 115,112,110,,to 11 terms

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Solution

(iv) 115,112,110,,to 11 termsFor this A.P.,a=115n=11d=a2a1=1121155460=160S11=112[2(115)+(111)160]=112[215+1060]=112[215+16]=112[4+530]=(112)(930)=3320

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