wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Question 1(iv)

Use a suitable identity to get each of the following products:
(3a12)(3a12)


Open in App
Solution

(3a12)(3a12)=(3a12)2
=(3a)22×3a×12+(12)2 [Using the identity (ab)2=a22ab+b2]
=9a23a+14


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon