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Question 1
Two line segments AB and AC include an angle of 60, where AB = 5 cm and AC = 7 cm. Locate points P and Q on AB and AC, respectively such that AP=34AB and AQ=14AC .Join P and Q measure the length PQ.
Thinking Process
(i) Firstly we find the ratio of AB in which P divides, it with the help of the relation AP=34AB
(ii) Secondly, we find the ratio of AC in which Q divides. It with the help of the relation AQ=14AC.
(iii) Now, construct the line segment AB and AC in which P and Q respectively divide it in the ratio from step (i) and (ii) respectively.
(iv) Finally get the point P and Q. After that join PQ and get the required measurement of PQ.


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Solution

(i) Given that AB=5cm and AP=34AB
AP=34AB=34×5=154cm
Then, PB=ABAP=5154=2054=54cm [ P is any point on the AB]
AP:PB=154:54AP:PB=3:1


(ii) Given that AC = 7 cm and AQ=14AC
AQ=14AB=14×7=74cm
Then, QC=ACAQ=774=2874=214cm [ Q is any point on the AC]
AQ:QC=74:214AP:PB=1:3


(iii) Steps of constructions:
1.Draw a line segment AB of length 5 cm
2.Draw a line segment AC of length 7 cm, making an angle 60 with AB
3.Now draw angular bisector of angle BAC (ray AX) such that it makes equal acute angle with AB and AC (i.e 30 )
4.Along AX mark 3 + 1 = 4 Points
A1,A2,A3,A4 such that
AA1=AA2=A2A3=A3A4
5. Join A4B
6. From A3, draw A3P||A4B meeting AB at P.
[By making an angle equal to BA4A at A3]
Then P is the point on AB which divides it in the ratio 3:1.
Thus AP : PB = 3 : 1
7. Join A4C
8.From A1, draw A1Q||A4C meeting AC at Q.
[By making an angle equal to CA4A at A1]
Then Q is the point on AC which divides it in the ratio 1:3.
Thus AQ : QC = 1:3
9. Join P and Q and measure the length.

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