Question

Question 10

Area of a rectangle with length 4ab and breadth $6b^2$ is
a) $24a^2{b}^2$
b) $24a{b}^3$
c) $24a{b}^2$
d) $24ab$

Answer 1

b) $24a{b}^3$
$\to$​​​​​​​We know that, area of a rectangle = Length $\times$ Breadth = $4ab\times 6b^2$
This is the product of two monomials.
$\therefore$ Area of rectangle $=(4\times 6)ab\times b^2=24a{b}^3$