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Question

Question 10
Factorise each of the following:
(i) 27y3+125z3
(ii) 64m3343n3

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Solution

(i)27y3+125z3=(3y)3+(5z)3[Using identity a3+b3=(a+b)(a2ab+b2)]=(3y+5z)[(3y)2(3y)(5z)+(5z)2]=(3y+5z)(9y215yz+25z2)

(ii)64m3343n3=(4m)3(7n)3[Using identity a3b3=(ab)(a2+ab+b2)]=(4m7n)[(4m)2+(4m)(7n)+(7n)2]=(4m7n)(16m2+28mn+49n2)

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