Question

Question 10.
I toss three coins together. The possible outcomes are no heads, 1 head, 2 head and 3 heads. So, I say that probability of no heads is $\frac{1}{4}$. What is wrong with this conclusion ?

Answer 1

I toss three coins together [given]
So, total number of outcomes $=2^3=8$
and possible outcomes are (HHH), (HTT), (THT), (TTH), (HHT), (THH), (HTH) and (TTT) Now, probability of getting no head $=\frac{1}{8}$
Hence, the given conclusion is wrong because the probability of no head is $\frac{1}{8}not\frac{1}{4}$