Question 10
One of the zeroes of the polynomial is 2x2+7x–4 is
A) 2
B) 12
C) −12
D) −2
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Solution
The answer is B.
Let p(x)=2x2+7x−4 =2x2+8x–x–4 [By splitting middle term] =2x(x+4)−1(x+4) =(2x–1)(x+4)
For zeroes of p(x), put p(x)=0. ∴(2x−1)(x+4)=0 ⇒2x−1=0 and x+4=0 ⇒x=12 and x=−4
Hence, one of the zeroes of the polynomial p(x) is 12.