(i) False. Zero of x – 3 is 3.
[∵x−3=0⇒x=3]
(ii) True. Zero of 3x+1 is−13.
[∵3x+1=0⇒x=−13]
(iii) False. Zero of 4 - 5y is45.
[∵4−5y=0⇒y=45]
(iv)True.
t2–2t=t(t–2)
Hence, zeroes of t2–2t are 0 and 2.
(v) True.
y2+y–6=y2+3y–2y–6 [ by splitting middle term]
=y(y+3)–2(y+3)
=(y−2)(y+3) ...(i) [equating equation(i) equal to zero]
Hence, the zeroes of y2+y–6 are 2 and -3.