Question

Question 102(ii)
Using suitable rearrangement, find the sum.
$-5+\frac{7}{10}+\frac{3}{7}+(-3)+\frac{5}{14}+\left(\frac{-4}{5}\right)$

Answer 1

Here,

$\Rightarrow -5+\frac{7}{10}+\frac{3}{7}+(-3)+\frac{5}{14}+\left(\frac{-4}{5}\right)$

$=-5+(-3)+\frac{7}{10}+\left(\frac{-4}{5}\right)+\frac{3}{7}+\frac{5}{14}$

$=-8+\frac{7-8}{10}+\frac{6+5}{14}$

$=-8-\frac{1}{10}+\frac{11}{14}$

$=\frac{-560-7+55}{70}$

$=\frac{-512}{70}$

$=\frac{-256}{35}$