Question 105
If 53x−1÷25=125, then find the value of x .
53x−1÷25=125
⇒53x−1÷(5)2=53
⇒5(3x−1)−2=53 [am÷an=am−n]
⇒53x−1−2=53
⇒53x−3=53
Since, the base is same on both sides, we can equate the exponents.
⇒3x−3=3⇒3x=6⇒x=2