Question 108iiiVerify the property x - y - y - x of rational numbers by usingx - -5-7 and y - 14-15

Given, x = 5/7 and y = 14/15 Then, LHS = x × y = 5/7×14/15 = 2/3 RHS = y × x = 14/15× 5/7 = 2/3 ∴ nbsp; LHS = RHS nbsp; nbsp;⇒ x × y = y × x Henc ...

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Standard IX

Mathematics

Rational Numbers

Question 108i...

Question

Question 108(iii)
Verify the property $x \times y = y \times x$ of rational numbers by using
$x = \frac{- 5}{7}$ and $y = \frac{14}{15}$

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Solution

Given, $x = \frac{- 5}{7}$ and $y = \frac{14}{15}$

Then,
$L H S = x \times y = \frac{- 5}{7} \times \frac{14}{15} = \frac{- 2}{3}$

$R H S = y \times x = \frac{14}{15} \times \frac{- 5}{7} = \frac{- 2}{3}$

$∴ L H S = R H S \Rightarrow x \times y = y \times x$

Hence verified.

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Similar questions

Q. Verify the property

x \times y = y \times x

of rational numbers by using

x = \frac{- 5}{7}

and

y = \frac{14}{15}

Question 108(ii)
Verify the property $x \times y = y \times x$ of rational numbers by using
$x = \frac{2}{3}$ and $y = \frac{9}{4}$

Question 109(iii)
Verify the property $x \times (y \times z) = (x \times y) \times z$ of rational numbers by using
$x = \frac{- 2}{7}, y = \frac{- 5}{6}$ and $z = \frac{1}{4}$
and what is the name of this property?

Question 109(ii)
Verify the property $x \times (y \times z) = (x \times y) \times z$ of rational numbers by using
$x = \frac{2}{3}, y = \frac{- 3}{7}$ and $z = \frac{1}{2}$
and what is the name of this property?

Question 109(iii)
Verify the property $x \times (y \times z) = (x \times y) \times z$ of rational numbers by using
$x = \frac{- 2}{7}, y = \frac{- 5}{6}$ and $z = \frac{1}{4}$
and what is the name of this property?

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Rational Numbers

Standard IX Mathematics

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Question 108(iii) Verify the property x×y=y×x of rational numbers by using x=−57 and y=1415

Given, x=−57 and y=1415 Then, LHS=x×y=−57×1415=−23 RHS=y×x=1415×−57=−23 ∴LHS=RHS⇒x×y=y×x Hence verified.

Question 108(iii)
Verify the property $x \times y = y \times x$ of rational numbers by using
$x = \frac{- 5}{7}$ and $y = \frac{14}{15}$

Given, $x = \frac{- 5}{7}$ and $y = \frac{14}{15}$

Then,
$L H S = x \times y = \frac{- 5}{7} \times \frac{14}{15} = \frac{- 2}{3}$

$R H S = y \times x = \frac{14}{15} \times \frac{- 5}{7} = \frac{- 2}{3}$

$∴ L H S = R H S \Rightarrow x \times y = y \times x$

Hence verified.