Question

Question 11
Diagram of the adjacent picture frame has outer dimensions = 24 cm $\times$ 28 cm and inner dimensions 16 cm $\times$ 20 cm. Find the area of each section of the frame, if the width of each section is same.

Answer 1

Given that, the width of each Section is same.
Therefore, IB = BJ= CK =CL = DM = DN = AO =AP

IL= IB +BC + CL
$\Rightarrow$28= IB + 20 +CL
$\Rightarrow$IB+CL =28cm - 20 cm = 8cm
$\Rightarrow$IB =CL = 4cm
Hence, IB =BJ=CK=CL=DM=DN=AO=AP=4cm
Area of Section BEFC =Area of section DGHA
$=\frac{1}{2}(20+28)\left(4\right)]c{m}^2=96c{m}^2$
Area of Section ABEH = Area of Section CDGF = Area of Section BEFC =Area of section DGHA = $96c{m}^2$