Question

Question 11 (ii)
State whether the following are true or false. Justify your answer.
(ii) sec A = $\frac{12}{5}$ for some value of angle A.

Answer 1

True. Let's see how -

Let a $\Delta$ABC in which $\angle B={90}^{\circ }$, AC be 12k and AB be 5k, where k is a positive real number.
By Pythagoras theorem; we get,
$A{C}^2=A{B}^2+B{C}^2$
$(12k{)}^2=(5k{)}^2+B{C}^2$
$144k^2=B{C}^2+25k^2$
$B{C}^2=119k^2$
Such a triangle is possible as it will follow the Pythagoras theorem.