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Question 11
In a Laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 5, 06,000.

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Solution

Her, Principal (P) = 5,06,000 ,
Rate of interest (R) = 2.5%
Time (n) = 2 hours

After 2 hours, number of bacteria,

Amount (A)
A=P(1+R100)n
=506000(1+2.5100)2
=506000(1+251000)2
=506000(1+140)2
=506000(4140)2
=506000×4140×4140
=5,31,616.25

Hence, number of bacteria after two hours are 531616 (approx.)

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