Question

Question 11
Is the area of the largest circle that can be drawn inside a rectangle of length a cm and breadth b cm $(a>b)is\pi b^{2}cm$? why?

Answer 1

As shown in figure, the radius of the largest circle inscribed in a rectangle will be equal to b.
Now, the area of this circle is $\pi$${\left(\frac{b}{2}\right)}^{2}cm$

Therefore, the given statement is true.