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Question 11
Size of agricultural holdings in a survey of 200 families is given in the following table
Size of agricultural holdings(in hec)Number of families05 10510 151015 301520 802025 402530 203035 5
Compute median and size of the holdings.

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Solution

Size of agricultural holdings(in hec)Number of families (fi)Cumulative frequency05 10 10510 15 251015 30 551520 80 1352025 40 1752530 20 1953035 5 200
(i) Here, N=200
Now, N2=2002=100, which lies in the interval 15-20.
Lower limit, l=15, h=5, f=80 and cf=55
Median=l+(N2cff)×h=15+(1005580)×5=15+(4516)=15+2.81=17.81hec
(ii) In a given table 80 is the highest frequency.
So, the modal class is 15-20.
Here , l=15, fm=80,f1=30,f2=40 and h=5
Mode=l+(fmf12fmf1f2)×h=15+(80302×803040)×5=15+(5016070)×5=15+(5090)×5=15×259=15+2.77=17.77 hec

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