Question

Question 11

The volume of a cube is $64c{m}^3.$ Its surface area is
(a) $16c{m}^2$ (b) $64c{m}^2$
(c) $96c{m}^2$ (d) $128c{m}^2$

Answer 1

Let the side of the cube be a. Then,
Volume of cube $a^3=64$
$\Rightarrow a=4$ [given]
Now, surface area of the cube$=6a^2=6\times 4^2=96c{m}^2$