Question 11
Two objects, each of mass 1.5 kg are moving in the same straight line but in opposite directions. The velocity of each object is $2.5 m s^{- 1}$ before the collision during which they stick together. What will be the velocity of the combined object after collision?

Open in App

Solution

Mass of one of the object, $m_{1} = 1.5$ kg
Mass of the other object, $m_{2}$ = 1.5 kg
Velocity of $m_{1}$ before collision, $u_{1}$ = 2.5 $m s^{- 1}$
Velocity of $m_{2},$ moving in opposite direction before collision, $u_{2}$ = -2.5 $m s^{- 1}$
Let v be the velocity of the combined object after collision.
By the law of conservation of momentum,
Total momentum after collision = Total momentum before collision,
Or, $(m_{1} + m_{2}) v = m_{1} u_{1} + m_{2} u_{2}$
Or, $(1.5 + 1.5) v = 1.5 \times 2.5 + 1.5 \times (- 2.5)$ [negative sign as moving in opposite direction]
Or, v = 0 $m s^{- 1}$

Suggest Corrections

Similar questions

Q. Question 11
Two objects, each of mass 1.5 kg are moving in the same straight line but in opposite directions. The velocity of each object is

2.5 m s^{- 1}

before the collision during which they stick together. What will be the velocity of the combined object after collision?

Q. Two objects, each of mass

1.5 k g

are moving in the same straight line but in opposite directions. The velocity of each object is

2.5 {m s}^{- 1}

before the collision during which they stick together. What will be the velocity of the combined object after the collision?

Q. Two objects of mass 1.5 kg are moving in same straight line but in opposite direction. The velocity of each object is 2.5 m/s before collision during which they stick together. What will be their combined velocity after collision

Two objects each of mass 1.5 kg are moving in the same straight line but in opposite directions. The velocity of each object is $2.5 m s^{- 1}$ before the collision during which they stick together. What will be the velocity of the combined object after the collision?