Question

Question 11 (vi)
In $\Delta ABC$ and $\Delta DEF$, AB=DE, AB || DE, BC =EF and BC ⃦EF. Vertices A, B and C are joined to vertices D, E and F respectively ( see the given figure). Show that $\Delta ABC\cong \Delta DEF$ .

Answer 1

$\Delta ABC$ and $\Delta DEF$,
AB=DE(Given)
BC=EF(Given)
AC=DF (ACFD is a parallelogram)
$\therefore \Delta ABC\cong \Delta DEF$ ( By SSS congruence rule).