Question

Question 11 (vi)
In \(\Delta ABC\) and \(\Delta DEF\), AB=DE, AB || DE, BC =EF and BC ⃦EF. Vertices A, B and C are joined to vertices D, E and F respectively ( see the given figure). Show that \(\Delta ABC \cong \Delta DEF\) .

Answer 1

$\Delta ABC$ and $\Delta DEF$,
AB=DE(Given)
BC=EF(Given)
AC=DF (ACFD is a parallelogram)
$\therefore \Delta ABC\cong \Delta DEF$ ( By SSS congruence rule).