Question

Question 118
A $117\frac{1}{3}m$ long rope is cut into equal pieces measuring $7\frac{1}{3}m$ each. How many such small pieces are these?

Answer 1

We have, length of rope
$=117\frac{1}{3}m$

$=\frac{117\times 3+1}{3}m=\frac{352}{3}m$

Length of each piece $=7\frac{1}{3}m=\frac{22}{3}m$

So, the number of pieces of the rope
$=\frac{Totallengthoftherope}{Lengthofeachpiece}$

$=\frac{\frac{352}{3}}{\frac{22}{3}}=\frac{352}{3}\times \frac{3}{22}=16$

Hence, number of small pieces cut from the $117\frac{1}{3}m$ long rope is 16.