Question 118

During school hours, Neha finished 73 % of her homework and Minakshi completed $\frac{5}{8}$ of her homework. Who must finish a greater per cent of homework ?

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Solution

Neha finished her homework in percentage = $73 % = \frac{73}{100}$
Where Minakshi completed = $\frac{5}{8}$ of her home work
Home work left for Minakshi = $1 - \frac{5}{8} = \frac{3}{8}$
In percentage = $\frac{3}{8} \times 100 = 37.5 %$
Home work left for Neha = (100 - 73) = 27 % = $\frac{27}{100}$
Hence, Minakshi finished a greater percentage of homework.

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Question 118 During school hours, Neha finished 73 % of her homework and Minakshi completed 58 of her homework. Who must finish a greater per cent of homework ?

Neha finished her homework in percentage = 73%=73100 Where Minakshi completed = 58 of her home work Home work left for Minakshi = 1−58=38 In percentage = 38×100=37.5% Home work left for Neha = (100 - 73) = 27 % =27100 Hence, Minakshi finished a greater percentage of homework.

Question 118

During school hours, Neha finished 73 % of her homework and Minakshi completed $\frac{5}{8}$ of her homework. Who must finish a greater per cent of homework ?