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Question

Question 12
Find the zeroes of the polynomial p(x)=(x2)2(x+2)2

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Solution

p(x)=(x2)2(x+2)2
For zeroes of polynomial, put p(x) = 0.
(x2)2(x+2)2=0
(x2+x+2)(x2x2)=0 [ Using identity, a2b2=(ab)(a+b) ]
(2x)(4)=0
8x=0
x=0 [80]
Hence, zero of the polynomial p(x) is 0.

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