Question

Question 12 (i)
A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see figure) and these are equally likely outcomes. What is the probability that it will point at 8?

Answer 1

Out of 8 numbers, an arrow can point any of the numbers in 8 ways.
$\therefore$ Total number of outcomes = 8
Favourable number of outcomes (arrow points at 8) = 1

Hence, P (arrow points at 8)
$=\frac{Favourablenumberofoutcomes}{Totalnumberofoutcomes}=\frac{1}{8}$