Question 12
If a=2+√3 , then find the value of (a−1a).
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Solution
We have a=2+√3
Then,1a=12+√3×2−√32−√3 [Multiplying numerator and denominator by (2−√3)] 2−√3(2)2−(√3)2=2−√34−3=2−√3 [Using identity (a+b)(a−b)=a2−b2] ⇒1a=2−√3∴a−1a=(2+√3)−(2−√3)=2+√3−2+√3=2√3