Question

Question 12 (iii)
A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see figure) and these are equally likely outcomes. What is the probability that it will point at a number greater than 2?

Answer 1

Out of 8 numbers, an arrow can point any of the numbers in 8 ways.
$\therefore$ Total number of outcomes = 8
Since, from among the numbers given, the numbers greater than 2 are 3,4,5,6,7 and 8
Hence, the favourable number of outcomes = 6

Hence, P (arrow points at a number > 2)
$=\frac{Favourablenumberofoutcomes}{Totalnumberofoutcomes}$=$\frac{6}{8}=\frac{3}{4}$