Question 13
An object weighs 10 N in air. When immersed fully in water, it weighs only 8 N. The weight of the liquid displaced by the object will be

(a) 2 N
(b) 8 N
(c) 10 N
(d) 12 N

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Solution

(a) 2 N

According to Archimedes principle,
Weight of liquid displaced = Weight in air - Weight in water = 10 - 8 = 2 N

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Q. Question 13
An object weighs 10 N in air. When immersed fully in water, it weighs only 8 N. The weight of the liquid displaced by the object will be

(a) 2 N
(b) 8 N
(c) 10 N
(d) 12 N

An object weighs 10 N in air. When immersed fully in a liquid, it weighs only 8 N. The weight of liquid displaced by the object will be :
(a) 2 N
(b) 8 N
(c) 10 N
(d) 12 N

Q. An object weighs 10 N in air. When immersed fully in water, it weighs only 8 N. The weight of the liquid displaced by the object will be

An object weighs 10N in air. When immersed fully in a liquid, it weighs only 8N.The weight of a liquid displaced by object will be:

Q. An object weighs

10 N

in air. When immersed fully in water, it weighs only

8 N .

The weight of the liquid displaced by the object will be:

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Application of The Principle of Flotation

Standard IX Physics

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Question 13 An object weighs 10 N in air. When immersed fully in water, it weighs only 8 N. The weight of the liquid displaced by the object will be (a) 2 N (b) 8 N (c) 10 N (d) 12 N​​​​​​​

(a) 2 N According to Archimedes principle, Weight of liquid displaced = Weight in air - Weight in water = 10 - 8 = 2 N

Question 13
An object weighs 10 N in air. When immersed fully in water, it weighs only 8 N. The weight of the liquid displaced by the object will be

(a) 2 N
(b) 8 N
(c) 10 N
(d) 12 N

(a) 2 N

According to Archimedes principle,
Weight of liquid displaced = Weight in air - Weight in water = 10 - 8 = 2 N