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Question

Question 13
The 4th term from the end of an AP – 11, –8, –5, ….., 49 is

A) 37
B) 40
C) 43
D) 58

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Solution

We know that, the nth term of an AP from the end is;
an=l(n1)d...(i)
Here,l=Last term=49 [given]

Common difference,
d = -8 - (- 11)
= -8 + 11 = 3

From eq. (i), The 4th term from the end
= 49 - (4 - 1)3 = 49 - 9 = 40

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