Question 137Evaluate- 62 - 821-23

Name: EXEMP - Grade 08 - Mathematics - Square-Square Root & Cube- Cube Root - Q137
Uploaded: 2022-07-04T10:36:42+05:30
Description: We have, {6^2 + (8^2)^1/2}^3 = {36+8}^3 = (44)^3 = 44 × 44 × 44 = 85184. ...

We have, {6^2 + (8^2)^1/2}^3 = {36+8}^3 = (44)^3 = 44 × 44 × 44 = 85184. ...

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Standard VII

Mathematics

Quotient Law of Exponent

Question 137E...

Question

Question 137

Evaluate: ${6^{2} + (8^{2})^{\frac{1}{2}}}^{3}$

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Solution

We have, ${6^{2} + (8^{2})^{\frac{1}{2}}}^{3} = {36 + 8}^{3} = (44)^{3} = 44 \times 44 \times 44 = 85184$ .

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Evaluate: ${6^{2} + (8^{2})^{\frac{1}{2}}}^{3}$

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Quotient Law of Exponent

Standard VII Mathematics

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Question 137 Evaluate: {62+(82)12}3

We have, {62+(82)12}3={36+8}3=(44)3=44×44×44=85184.

Question 137

Evaluate: ${6^{2} + (8^{2})^{\frac{1}{2}}}^{3}$

We have, ${6^{2} + (8^{2})^{\frac{1}{2}}}^{3} = {36 + 8}^{3} = (44)^{3} = 44 \times 44 \times 44 = 85184$ .