Question

Question 14
Velocity versus time graph of a ball of mass 50 g rolling on a concrete floor is shown in Figure given below. Calculate the acceleration and frictional force of the floor on the ball.

Answer 1

Given, initial velocity, $u=80m{s}^{-1}$, final velocity, $v=0$, mass, $m=50g=\frac{50}{1000}=0.05kg$ and time, $t=8s$.
Acceleration $=a=\frac{v-u}{t}=-\frac{80}{8}m{s}^{-2}=-10m{s}^{-2}$
As, there is only frictional force acting on the body, so
force $F=ma=0.05\times 10=0.5N$