Question 15
A pole 6m high casts a shadow 2√3 m long on the ground, then the Sun’s elevation is
(A) 60∘
(B) 45∘
(C) 30∘
(D) 90∘
The answer is (A).
Let BC = 6m be the height of the pole and AB=2√3m be the length of the shadow on the ground.
Let the Sun makes an angle θ on the ground.
Now, in ΔBAC, tanθ=BCAB
⇒tanθ=62√3=3√3×√3√3
⇒tanθ=3√33=√3=tan60∘
∴θ=60∘
Hence, the Sun’s elevation is 60∘