Total sum of money = ₹300
Let the number of ₹5 coins be x,
Number of ₹2 coins be 3x and
Number of ₹1 coins be 160−(x+3x)=(160−4x).
According to question,
5×x+2×(3x)+1×(160−4x)=300
⇒5x+6x+160−4x=300
⇒7x+160=300
⇒7x+160−160=300−160 [Subtracting 160 from both sides]
⇒7x=140
⇒7x7=1407 [Dividing both sides by 7]
⇒x=20
Hence,the number of coins of ₹5 denomination
=20
Number of coins of ₹2 denomination
=3×20=60
Number of coins of ₹1 denomination
=160–4×20=160–80=80