Question 15
The graph of the linear equation y = x passes through the point:

A) $(\frac{3}{2}, - \frac{3}{2})$
B) $(0, \frac{3}{2})$
C) $(1, 1)$
D) $(- \frac{1}{2}, \frac{1}{2})$

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Solution

The answer is C.
The linear equation y = xhas the same value of x and y-coordinates.
Therefore, the point (1, 1)must lie on the line y = x.

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Question 5
The graph of the linear equation 2x + 3y = 6 cuts the y-axis at the point:

A) (2, 0)
B) (0, 3)
C) (3, 0)
D) (0, 2)

The graph of the line x - y = 0 passes through the point

(a) $\frac{- 1}{2}, \frac{1}{2}$

(b) $\frac{3}{2}, \frac{- 3}{2}$

(d) (1, 1)

The equation of the line passing through $(2, 0)$ and $(0, 3)$ is $\frac{x}{2} + \frac{y}{3} = 1$

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