Let the cost of 1st prize be P.
Cost of 2nd prize = P − 20
And cost of 3rd prize = P − 40
It can be observed that the cost of these prizes are in an A.P. having common difference as −20 and first term as P.
a = P
d = - 20
Given that, S7=700
72[2a+(7−1)d]=70072[2a+(7−1)d]=700[2a+(6)(−20)]2=100a−3(20)=100a−60=100a=160
Therefore, the value of each of the prizes was Rs. 160, Rs. 140, Rs. 120, Rs. 100, Rs. 80, Rs. 60, and Rs. 40.