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Question

Question 16
What are the possible expressions for the dimensions of the cuboids whose volumes are given below?
Volume:3x212x(i) Volume:12ky2+8ky20k(ii)

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Solution

(i) Volume of cuboid=abc=3x212x=3x(x4)

3, x(x-4) are the three factors.
So, these can be the three dimensions.

(ii) Volume of cuboid=abc=12ky2+8ky20k=4k(3y2+2y5)=4k[3y(y1)+5(y1)]=4k(y1)(3y+5)

4k, (y-1) and (3y+5) are the three factors.
Hence, these can be the three dimensions.

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