Question 17 (ii)
(ii) Suppose the bulb drawn in (i) is not defective and is not replaced. Now one bulb is drawn at random from the rest. What is the probability that this bulb is not defective?
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Solution
(ii) Now total number of favourable outcomes = 20 - 1 = 19
Number of favourable outcomes = 19 - 4 = 15
Hence, P (getting a non-defective bulb) = 1519