1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Mathematics
Differentiation Using Substitution
Question 18 ...
Question
Question 18
18
.
c
o
t
-
1
cos
α
1
/
2
-
tan
-
1
cos
α
1
/
2
=
x
,
t
h
e
n
sin
x
=
(
A
)
tan
2
α
2
B
c
o
t
2
α
2
C
tan
α
D
tan
α
2
Open in App
Solution
Dear student
x
=
cot
-
1
cosα
-
tan
-
1
cosα
x
=
π
2
-
tan
-
1
cosα
-
tan
-
1
cosα
x
=
π
2
-
2
tan
-
1
cosα
x
=
π
2
-
cos
-
1
1
-
cosα
2
1
+
cosα
2
As
2
tan
-
1
x
=
cos
-
1
1
-
x
2
1
+
x
2
x
=
π
2
-
cos
-
1
1
-
cosα
1
+
cosα
x
=
π
2
-
cos
-
1
tan
2
α
2
cos
-
1
tan
2
α
2
=
π
2
-
x
tan
2
α
2
=
cos
π
2
-
x
tan
2
α
2
=
sinx
Regards
Suggest Corrections
0
Similar questions
Q.
2
t
a
n
−
1
(
c
o
s
x
)
=
t
a
n
−
1
(
c
o
s
e
c
2
x
)
,then x=
Q.
If
x
=
sin
−
1
(
a
6
+
1
)
cos
−
1
(
a
4
+
1
)
−
tan
−
1
(
a
2
+
1
)
,
a
ϵ
R
, then the value of
sec
2
x
is
Q.
Evaluate the following:
(i)
sin
-
1
sin
5
π
6
(ii)
cos
-
1
cos
-
π
4
(iii)
tan
-
1
tan
3
π
4
(iv)
sin
-
1
(
sin
2
)
(v)
sin
π
3
-
sin
-
1
-
3
2
(vi)
cos
cos
-
1
-
3
2
+
π
4
(vii)
cos
tan
-
1
3
4
(viii)
cos
-
1
cos
5
π
4
(ix)
cos
-
1
cos
4
π
3
(x)
tan
-
1
tan
2
π
3
(xi)
cos
-
1
cos
13
π
6
(xii)
tan
-
1
tan
7
π
6
Q.
cos
−
1
(
cos
(
−
5
)
)
+
sin
−
1
(
sin
(
6
)
)
−
tan
−
1
(
tan
(
12
)
)
is equal to
(The inverse trigonometric functions take the principal values)
Q.
cos
[
cos
−
1
cos
[
8
π
7
]
+
tan
−
1
tan
[
8
π
7
]
]
has the value equal to -
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Method of Substitution
MATHEMATICS
Watch in App
Explore more
Differentiation Using Substitution
Standard XII Mathematics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app