Question 19
Find and correct the errors in the statement: $\frac{3}{4 x + 3} = \frac{1}{4 x}$

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Solution

$L . H . S = \frac{3}{4 x + 3} \neq R . H . S T h e c o r r e c t s t a t e m e n t i s \frac{3}{4 x + 3} = \frac{3}{4 x + 3}$

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Similar questions

\frac{3}{4 x + 3} = \frac{1}{4 x}

\frac{4 x + 5}{4 x} = 5

\frac{4 x + 5}{4 x} = 5

4 (x - 5) = 4 x - 5

4 (x - 5) = 4 x - 5

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